M Inbox (68) - luketry@gmail.com - x VA Sec 3.4 Derivatives as Rates of Ch x Course Hero x C Calculus question | Chegg.com + X G webassign.net/web/Student/Assignment-Responses/last?dep=28194863 DOTAL Additional Materials Reading Submit Answer 5. [-/17 Points] DETAILS OSCALC1 3.4.165. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A culture of bacteria grows in number according to the function /(t), where t is measured in hours. N (t ) = 2000 1 + 72 + 100 4t (a) Find the rate of change of the number of bacteria. N'(t) = (b) Find N'(0), N'(10), N'(20), and N'(30). N'(0) = N'(10) = N'(20) = N'(30) = (c) Interpret the results from part (b). At t = 0 hours, the bacteria population is -Select- v . At t = 10 hours, the bacteria population is [---Select-- v . At t = 20 hours, the bacteria population is -Select-- . And at t = 30 hours, the bacteria population is [---Select-- v (d) Find /"(0), N"(10), N"(20), and N"(30). N"(0) = N"(10) = N"(20) = N"(30) = Interpret what the answers imply about the bacteria population growth. At t = 0 hours, the rate at which the bacteria population is changing is [--Select- v . Att = 10 hours, the rate at which the bacteria population is changing is [-Select--- v . At t = 20 hours, the rate at which the bacteria population is changing is [---Select-- v . Att = 30 hours, the rate at which the bacteria population is changing is -Select- v. Additional Materials Reading 69.F 7:51 PM 3/20/2022 22 Sunny