mainly need help on part c last picture thank you

A one-way analysis of variance experiment produced the following ANOVA table. Assume normality in the underlying population (You may find it useful to reference the g table). SUMMARY \begin{tabular}{|l|c|c|} \hline SUMMARY & \multicolumn{2}{|l|}{} \\ \hline Groups & Count & Average \\ \hline Column 1 & 6 & 0.57 \\ \hline Column 2 & 6 & 1.38 \\ \hline Column 3 & 6 & 2.33 \\ \hline \end{tabular} \begin{tabular}{|l|c|c|c|c|c|} \hline ANOVA \\ \hline Source of Variation & SS & df & MS & F & p-value \\ \hline Between Groups & 9.12 & 2 & 4.56 & 12.84 & 0.0006 \\ \hline Within Groups & 5.33 & 15 & 0.36 & & \\ \hline & & & & & \\ \hline Total & 14.46 & 17 & & & \\ \hline \end{tabular} a. Conduct an ANOVA test at the 5% significance level to determine if some population means differ. Reject H0; we can conclude that some population means differ. Reject H0; we cannot conclude that some population means differ. Do not reject H0; we can conclude that some population means differ. Do not reject H0; we cannot conclude that some population means differ. b. Calculate 95\% confidence interval estimates of 12,13, and 23 with Tukey's HSD approach. (If the exact value for m - c is not found in the table, then round down. Negative values should be indicated by a minus sign. Round your answers 2 decimal places.) c. Given your response to part b, which means significantly differ