Majesty Video Production Incorporated wants the mean length of its advertisements to be 22 seconds. Assume the distribution of ad length follows the normal distribution with a population standard deviation of 2 seconds. Suppose we select a sample of 10 ads produced by Majesty.

b. What is the standard error of the mean time? (Round your answer to 2 decimal places.)

c. What percent of the sample means will be greater than 23.50 seconds? (Round your z-value and final answer to 2 decimal places.) d. What percent of the sample means will be greater than 20.50 seconds? (Round your z-value and final answer to 2 decimal places.) e. What percent of the sample means will be greater than 20.50 but less than 23.50 seconds? (Round your z-value and final answer to 2 decimal places.) f. What is the probability that the sampling error would be more than 1.5 hours? (Round your z-value and final answer to 4 decimal places.)