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MARR =10% per year. (1hp=0.746kW) a. If electricity costs $X per kilowatt-hour, calculate the annual cost of electrical power for each motor b. What cost
MARR =10% per year. (1hp=0.746kW) a. If electricity costs $X per kilowatt-hour, calculate the annual cost of electrical power for each motor b. What cost of electricity ( $/kWh ) makes the two pumps breakeven (i.e. have the same equivalent annual cost)? Assume repeatability and MVs =$0. c. Choose the graph to illustrate your answer to Part (b). d. Which motor should be selected? Click the icon to view the datatable for the additional information about two alternatives. Click the icon to view the interest and annuity table for discrete compounding when the MARR is 10% per year. More Info More Info MARR =10% per year. (1hp=0.746kW) a. If electricity costs $X per kilowatt-hour, calculate the annual cost of electrical power for each motor b. What cost of electricity ( $/kWh ) makes the two pumps breakeven (i.e. have the same equivalent annual cost)? Assume repeatability and MVs =$0. c. Choose the graph to illustrate your answer to Part (b). d. Which motor should be selected? Click the icon to view the datatable for the additional information about two alternatives. Click the icon to view the interest and annuity table for discrete compounding when the MARR is 10% per year. More Info More Info
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