mass if malachite: $0\mathrm{.}0683$g

mass of beaker $1$: $29\mathrm{.}3025$g

mass of HCl: $5\mathrm{.}1519$g

mass if beaker $1$ and solution after reaction: $34\mathrm{.}4774$g

mass of control beaker $2$: $27\mathrm{.}6040$g

mass of control HCl: $5\mathrm{.}3268$g

mass of control beaker $2$ and solution after reaction: $32\mathrm{.}9027$g

Assume that the mass loss from your malachite upon digestion with HCl is due to loss of CO$2$ gas which comes from the carbonate ion. How many moles of CO$2$ were released from the malachite sample? Show your calculations. $($Hint: control beaker$).$