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MATLAB question: Create a data structure named element to store information about elements in the periodic table. The data structure should have the following fields:
MATLAB question:
Create a data structure named element to store information about elements in the periodic table. The data structure should have the following fields: name, symbol, atomicNumber, atomicWeight, and electrons. The name and symbol fields are strings. The atomicNumber field is an integer while the atomicWeight has double precision type. The electrons field is a seven-element vector for the number of electrons in each valence shell. (a) Fill the structure with the data for the element Helium, which has the following properties: name = helium, symbol = He, atomicNumber = 2, atomic Weight = 4.0, and electrons = [2 0 0 0 0 0 1]. Set p2a = element. (b) Put the structure in part (a) into p2b and modify p2b so that the new name is Helium. (c) Put the structure in part (b) into p2c and modify p2c so that the new atomicWeight is 4.002602. (d) Put the structure in part (c) into p2d and modify p2d so that the new value of the last element of the electrons field is 0. Create a data structure named element to store information about elements in the periodic table. The data structure should have the following fields: name, symbol, atomicNumber, atomicWeight, and electrons. The name and symbol fields are strings. The atomicNumber field is an integer while the atomicWeight has double precision type. The electrons field is a seven-element vector for the number of electrons in each valence shell. (a) Fill the structure with the data for the element Helium, which has the following properties: name = helium, symbol = He, atomicNumber = 2, atomic Weight = 4.0, and electrons = [2 0 0 0 0 0 1]. Set p2a = element. (b) Put the structure in part (a) into p2b and modify p2b so that the new name is Helium. (c) Put the structure in part (b) into p2c and modify p2c so that the new atomicWeight is 4.002602. (d) Put the structure in part (c) into p2d and modify p2d so that the new value of the last element of the electrons field is 0Step by Step Solution
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