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MATLAB Question: (Is supposed to be quite easy, not really engineering knowledge needed ) Given: Note: Re = (D.V.density)/viscosity ; where V = Q/((pi*D^2)/4) I
MATLAB Question: (Is supposed to be quite easy, not really engineering knowledge needed )
Given:
Note: Re = (D.V.density)/viscosity ; where V = Q/((pi*D^2)/4)
I think i'm supposed to do an iteration with a "while / if" statement?
1 1.254 ti -1.741n E/D + (1) f Ref 3.708 where Re is the non-dimensional Reynolds number and and D are the absolute roughness and nominal diameter of the pipe. Problem Statement Consider a rugose commercial pipe with a nominal diameter of D=0.1 m and a roughness of E = 0.1 mm. Water flows over a length of L = 100 m at a rate of Q= 10 L.s-?. Properties of liquid water @ 20 C: density, p = 1 g.cm; viscosity, u = 1 cP. Deliverables 1. Given the above conditions, prove by plotting on the same graph both the left hand side and right hand side of equation (1), that the Colebrook friction factor equation has exactly one solution in the range 0.001Step by Step Solution
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