MAX S.T. 100X+120X+150X,+125X. 1) X+2X+2X+2X,108 2) 3X+5X+ X5 120 3) Xi X 25 4) XXX 50 XXXX20 OPTIMAL SOLUTION Objective Function Value-7475.000 Variable Vale Reduced Cost 8,000 0.000 X 0.000 5.000 X 17.000 0.000 X 33.000 0.000 Constraint Slack Surplus Dual Price 0.000 75.000 63.000 0.000 0.000 25.000 0.000 -25.000 OBJECTIVE COEFFICIENT RANGES Variable Lower Limit Current Valu Upper Limit X 87.500 100.000 No Upper Limit X2 No Lower Limit 120.000 125.000 Xi 125.000 150.000 162.500 120.000 125.000 150.000 RIGHT HAND SIDE RANGES Constraint 1 2 4 G Lower Limit Current Vabas 100.000 57,000 8.000 41.500 108.000 120.000 25.000 50.000 Upper Limit 123.750 No Upper Limit 58.000 54.000 Dashboard Calendar To Do Notifications Inbox 3) Use the following output to answer the questions. What would happen to dual price values if the right-hand side of constraint 1 increased by 1, right hand side of constrain 2 decreased by 5 and right-hand side of constraint 3 increased by 5 units simultaneously? What is the new optimal objective function value? 5. Which constraints are binding? What would happen to the optimal solution if the coefficient of X: increased by 2 and coefficient of X, decrease by 2? What is the new optimal value? Which constrain(s) have surplus variable(s)? What is the dual problem? Use the dual prices and constraints to show the objective function value is optimal. Dashboard Calendar To Do Notifications Inbox