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Maximizecontribution=3X1+5X2+7X31X1+7X2+4X3100(C1:hoursonmachine1)2X1+1X2+7X3110(C2:hoursonmachine2)8X1+4X2+1X3100(C3:hoursonmachine3)x1,x2,x30 a) Using a computer software for solving LP, the optimal solution achieved is: x1=7.95(roundyourresponsetotwodecimalplaces).x2=5.95(roundyourresponsetotwodecimalplaces).x3=12.59(roundyourresponsetotwodecimalplaces). Contribution (objective value) =141.77 (round your response to two decimal
Maximizecontribution=3X1+5X2+7X31X1+7X2+4X3100(C1:hoursonmachine1)2X1+1X2+7X3110(C2:hoursonmachine2)8X1+4X2+1X3100(C3:hoursonmachine3)x1,x2,x30 a) Using a computer software for solving LP, the optimal solution achieved is: x1=7.95(roundyourresponsetotwodecimalplaces).x2=5.95(roundyourresponsetotwodecimalplaces).x3=12.59(roundyourresponsetotwodecimalplaces). Contribution (objective value) =141.77 (round your response to two decimal places). b) Machine 1 has 0.00 hours of unused time available at the optimal solution (round your response to two decimal places). Machine 2 has 0.00 hours of unused time available at the optimal solution (round your response to two decimal places). Machine 3 has 0.00 hours of unused time available at the optimal solution (round your response to two decimal places). c) An adotional hour of time availabie for third machine, is worth 0.14 dollars to the firm (round your response to two decimal plac c) An additional 8 hours of time available for the second machine, at no cost to the firm, are going to increase the objective value b
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