Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

me understand the below : In this article, we consider minimizers of the functional X f ax jDuj dx; where X Rn is open and

me understand the below : In this article, we consider minimizers of the functional X f ax jDuj dx; where X Rn is open and bounded and u : X ! RN. We show that even though the coefficient a satisfies only that a 2 W1;q loc X \ L1X, it nonetheless follows that u is partially Holder continuous on the set of regular points of Da. We note that the integrability exponent q > 1 is arbitrary, and so, the coefficient map x 7! ax can be very irregular. As an application we show that weak solutions of the elliptic system r a x f 0 a x jDuj Du jDuj 0; x 2 X satisfies the same partial Holder continuity. The model case we have in mind is r a x jDuj p2 Du 0: Finally, we also demonstrate that Du is also almost everywhere Holder continuo

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Students also viewed these Mathematics questions

Question

LO2 Classify consumer products

Answered: 1 week ago