Meaning CON (LH) R R-_-CON(LM) 0 CON(LM) OC Instruction 0 LOAD Lbl 1 STORE Lb1 2 CLEAR Lbl 3 ADD Lbl INCREMENT Lbl CON(LH)+1CON(LH) 5 SUBTRACT Lbl R-CON(LH) R 6 DECREMENT LblCON(LH) _1_ COMLb1) 7 COMPARE Lblif CON(Lbl) > R then GT 1 else 0 if CON(LM) = R then EQ = 1 else 0 if CON(Lbl)