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Methyl dichloroacetate Cl2CHCO2CH3 (MW = 143) is hydrolyzed into methanol CH3OH according to the stoichiometric reaction: Cl2CHCO2CH3 + H2O = CH3OH + Cl2CHCO2H. The initial

Methyl dichloroacetate Cl2CHCO2CH3 (MW = 143) is hydrolyzed into methanol CH3OH according to the stoichiometric reaction: Cl2CHCO2CH3 + H2O = CH3OH + Cl2CHCO2H. The initial concentration of Cl2CHCO2CH3 prior to hydrolysis was 2 mg/L (0.014 mM), and the equilibrium concentration was 1.2 mg/L (0.0084 mM). The concentration of CH3OH at equilibrium is:

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