Question
Min 8x+12Y s.t. 1x+3Y>=7 2x+2Y>=10 6x+2Y>=14 x,y>=0 (a) Use the graphical solution procedure to find the optimal solution. What is the value of
Min 8x+12Y\ s.t. \ 1x+3Y>=7\ 2x+2Y>=10\ 6x+2Y>=14\ x,y>=0
\ (a) Use the graphical solution procedure to find the optimal solution.\ What is the value of the objective function at the optimal solution?\
at (x,n)=(,)
\ (b) Assume that the objective function coefficient for
x
changes from 8 to 6 . Use the graphical solution procedure to find the new optimal solution.\ Does the optimal solution change?\ The extreme point
(x,y)=1
\ remains
optimal. The value of the objective function becomes [ solution.\ Does the optimal solution change?\ The extreme point
(x,n)=1
\ becomes
optimal. The value of the objective function becomes 4 !\ (d) The computer solution for the linear program in part (a) provides the following objective coefficient range information.\ \\\\table[[Variable,\\\\table[[Objective],[Coefficient]],\\\\table[[Allowable],[Increase]],\\\\table[[Allowable],[Decrease]]],[
x
,8.00000,4.00000,4.00000],[
Y
,12.00000,12.00000,4.00000]]
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