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Minimum cost = 5 0 x 1 + 1 0 x 2 + 7 5 x 3 subject to x 1 - x 2 =

Minimum cost =50x1+10x2+75x3
subject to
x1-x2=1,000
2x2+2x3=2,000
x11,500
Solve the problem by the simplex method. Provide only the value of the basic variables at tableau #3.
Notes:
Set M=100.
Tableau #1 is the initial tableau where an inconsistency exists on row z.
Tableau #2 is the tableau where the inconsistency on row z is fixed.
Select one:
x1=1000,x3=2000,s1=0
x3=1000,x1=2150,x2=1500
None of the options provided
A1=1000,A2=2000,s1=1500
x1=1000,x3=1000,s1=500
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