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MINITAB was used to fit the model below to n = 15 data points, where x1 = 1 if level 2 0 if not and

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MINITAB was used to fit the model below to n = 15 data points, where x1 = 1 if level 2 0 if not and X2 = 1 if level 3 . Complete parts a through d. 0 if not y = Bo + ByX1 + B2x2 + e Click the icon to view the MINITAB output. a. Report the least squares prediction equation. (Type integers or decimals.) b. Interpret the values of p, and P2- B, estimates the difference in the mean value of the |variable between level and the base level of the qualitative variable. B2 estimates the difference in the mean value of the |variable between level and the base level of the qualitative variable c. Interpret the following hypotheses in terms of #1 , H2, and #3- Ho- By = P2 =0 - X He : At least one of the parameters , and B2 differs from 0. Data table The hypothesis Ho: B, = P2 = 0 is the same as Ho: The hypothesis He : At least one of the parameters , and B2 differs from 0 is the same as He: The regression equation is Y = 70.0+ 17.0 X1 + 40.2 X2 d. Conduct the hypothesis test of part c. Use a = 0.05. What is the test statistic? Predictor Coef SE Coef T The test statistic is Constant 70.000 4.236 16.53 0.000 (Type an integer or a decimal.) X1 17.000 5.881 2.89 0.014 X2 40.200 5.881 6.84 0.000 What is the p-value? S = 9.129 R-Sq = 80.5% R-Sq(adj) = 77.2% The p-value is. (Type an integer or a decimal.) Analysis of Variance What is the conclusion from the hypothesis test? Source DF SS MS F P Regression 4126.9 2063.5 24.77 0.000 Residual Error 12 1000.0 83.3 O A. There is sufficient evidence to indicate at least one of the means is different at a = 0.05. Total 14 5126.9 O B. There is sufficient evidence to indicate x, is at level 2 about 95% of the time. O C. There is sufficient evidence to indicate x2 is at level 3 about 95% of the time. O D. There is insufficient evidence to indicate at least one of the means is different at a = 0.05. Print Done

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