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Mitch throws a baseball straight up in the air from a cliff that is 48 ft high. The initial velocity is 48 ft/sec. The height
Mitch throws a baseball straight up in the air from a cliff that is 48 ft high. The initial velocity is 48 ft/sec. The height (in feet) of the baseball after t sec is given by2 16 48 48h t t= + + . Find the time at which the height of the baseball is 64 ft. Round answers to the nearest hundredth of a second
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