Module 1 Problem 3

(109%) Problem 3: Four point charges of equal magnitude @ = 45 nC are placed on the corners of a rectangle of sides D1 = 29 cm and D, = 11 cm. The charges on the left side of the rectangle are positive while the charges on the right side of the rectangle are negative. Refer to the figure.\f& 14% Part (a) Which of the following represents a free-body diagram for the charge on the lower left hand comer of the rectangle? Grade Summary O O O Deductions 096 Potential 10096 Submissions Attempts remaining: 4 (2596 per attempt) detailed view O O Submit Hint Feedback I give up! Hints: 0 for a 096 deduction. Hints remaining: _0 Feedback: 09% deduction per feedback.14% Part (b) Choose an expression for the horizontal component of the net force acting on the charge located at the lower left corner of the rectangle in terms of the charges, the given distances, and the Coulomb constant. Use a coordinate system in which the positive direction is to the right and upwards. Grade Summary O O O Deductions 096 Potential 1009% Fx = koz F, = kQ2 D. D1 + 3/2 3/7 Fx = kQ2 Submissions (D2 + D;) (DP + D;) (D; + D;) Attempts remaining: 3 (3396 per attempt) O detailed view Fx = kQ- 3/2 (D7 + D]) Submit Hint Feedback I give up! Hints: 0 for a 096 deduction. Hints remaining: _0 Feedback: 09% deduction per feedback.& 14% Part (c) Calculate the value of the horizontal component of the net force, in newtons, on the charge located at the lower left comer of the rectangle. Grade Summary Deductions 096 Potential 1009% sin() cos() tan() 7 HOME Submissions cotan( ) asin() acos() F 5 Attempts remaining 10 (596 per attempt) atan( ) acotan() sinh() 1 2 3 detailed view cosh( tanh() cotanh() 0 END O Degrees O Radians NO HACKSPACE CLEAR Submit Hint Feedback I give up! Hints: 0 for a 096 deduction. Hints remaining: _0 Feedback: 096 deduction per feedback.& 14% Part (d) Enter an expression for the vertical component of the net force acting on the charge located at the lower left corner of the rectangle in terms of the charges, the given distances, and the Coulomb constant. Assume up is positive. Grade Summary O O O Deductions 096 Potential 1009% D D F = kQ F = koz D2 3/2 3/2 3/2 Submissions (D + D; ) (D + DH) Attempts remaining: 3 O (3396 per attempt) detailed view F = koz 3/2 (D= + D;) Submit Hint Feedback I give up! Hints: 0 for a 096 deduction. Hints remaining: _0 Feedback: 09% deduction per feedback.14% Part (e) Calculate the value of the vertical component of the net force, in newtons. Grade Summary Deductions 096 Potential 1009% sin() cos( tan( 7 9 HOME Submissions Attempts remaining: 10 cotan() asin( acos() E 5 h (596 per attempt) atan() acotan() sinh() 1 2 3 detailed view cosh() tanh() cotanh() END O Degree: O Radians HACKSPACE CLEAR Submit Hint Feedback I give up! Hints: 0 for a 096 deduction. Hints remaining: _0 Feedback: 096 deduction per feedback.&14% Part (f) Calculate the magnitude of the net force, in newtons, on the charge located at the lower left corner of the rectangle. Grade Summary F = Deductions 096 Potential 1009% sin() COs() tan() HOME Submissions Attempts remaining 10 cotan( ) asin() acosO F 5 (596 per attempt) atan( ) acotan() sinh() 1 3 detailed view cosh() tanh() cotanh() END O Degrees O Radians NO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints: 0 for a 096 deduction. Hints remaining: 0 Feedback: 096 deduction per feedback.14% Part (g) Calculate the angle, in degrees between -180 and +1805, that the net force makes, measured from the positive horizontal direction. Grade Summary 9 = Deductions 090 Potential 1009% sin() cosO tan( 7 9 HOME Submissions Attempts remaining 10 cotan() asin() acos() E 4 5 (596 per attempt) atan() acotan() sinh() 2 3 detailed view cosh() tanh() cotanh() 0 END O Degrees O Radians BACKSPACE CLEAR Submit Hint Feedback I give up! Hints: 0 for a 096 deduction. Hints remaining: _0 Feedback: 096 deduction per feedback