Moist air enters the dehumidifier at 38^oC , and two streams exit the separator in vapor-liquid equilibrium. The exiting vapor stream flows at 0.420 mol/s at 5.8^oC and 7.6 mmHg (gauge). The exiting liquid stream is pure water flowing at 0.890 L/hr. Additional information/data: PV = nRT; y_iP = x_iP_i^sat; STP conditions: P=1.00 atm, T=273K, v = 22.4 L/mol; _{water(liquid)} = 1.0 g/cm³; MW_W = 18; MW_A = 29; Antoine equation and parameters: log₁₀(P^sat) = A B/(T+C), where P^sat = vapor pressure (mmHg) and T = temperature (^oC). For Air: A=6.73, B=286, C=270; For Water: A=8.06, B=1724, C=233.

a. Draw and label a process flow diagram. Number the streams. Clearly label the components (water=W, air=A) in each stream. Label phase of each stream (s=solid, l=liquid, g=gas).

b. Find the mole fraction of each component exiting from the vapor stream.

c. Find the mole fractions and overall flowrate (mol/min) in the feed.\

d. If the outlet temperature drops by 10%, the inlet mole fraction of water would:

INCREASE , DECREASE or STAY THE SAME