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mole fraction for ammonia, hydrogen and nitrogen Required information For the ammonia synthesis reaction, N2(9) + 3H2(9) - 2NH3(g) the equilibrium conversion to ammonia is

mole fraction for ammonia, hydrogen and nitrogen
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Required information For the ammonia synthesis reaction, N2(9) + 3H2(9) - 2NH3(g) the equilibrium conversion to ammonia is large at 300 K but decreases rapidly with increasing 7. However, reaction rates become appreciable only at higher temperatures. For a feed mixture of hydrogen and nitrogen in the stoichiometric proportions, determine the following: (Take the value of Rto be 8.314 J.morl" For data, use the heat capacities of gases in the ideal-gas state table and the enthalpy and Gibbs energy of formation of the species table.) NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. What is the equilibrium mole fractions of ammonia, nitrogen, and hydrogen at 1 bar and 300 K? The mole fractions are YN2 is 0.25 2 is 0.25 YNH3 is 0.5

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