Question
Molecular iodine, I2(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s-1. (a) What is the half-life for this
Molecular iodine, I2(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s-1. (a) What is the half-life for this reaction? Correct: Your answer is correct. s (b) If you start with 0.052 M I2 at this temperature, how much will remain after 5.02 s assuming that the iodine atoms do not recombine to form I2?. M
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Biochemistry Concepts and Connections
Authors: Dean R. Appling, Spencer J. Anthony Cahill, Christopher K. Mathews
1st edition
321839927, 978-0133853490, 133853497, 978-0321839923
