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prove that d [r.(vxa)]=r-(vxa). dt

prove that \( \frac{d}{d t}[\mathbf{r} \cdot(\mathbf{v} \times \mathbf{a})]=\mathbf{r} \cdot(\mathbf{v} \times \dot{\mathbf{a}}) \) 

d [r.(vxa)]=r-(vxa). dt

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