My code is below and I have to get my code to look like the code below. I haven't been able to get in right please help.

Is it possible to put in the wrong file.txt name and have the code restart instead of throwing an error?

TXT FILE

12-30-2020 313 HellO! Bye235 11 Cdc What? Not now! Tues abba HILLS 02-29-2019 78087 444-22-888 9878 7

MY CODE

import os

from datetime import datetime

#file name input

def readData():

all=[]

file=input('Enter file name with extension: ')

if os.path.isfile(file):

fobj = open (file , "r")

tmpStr = fobj.read()

Lines = file1.readlines()

for line in Lines:

all=line.strip(' ')

all.append(x)

else:

return []

#I found strptime online at programwiz and on the python glossary.

#I used it beacuse it creates a datetime from the string/file

def isValidDate(string):

try:

if string != datetime.strptime(string, "%m-%d-%Y").strftime('%m-%d-%Y'):

raise ValueError

return True

except ValueError:

return False

#Reverse to see if the string is eqaul or not.

def isPalindrome(string):

rev = reversed(string)

if list(string) == list(rev):

return True

return False

#Accepts a string and checks to see how many letters are uppercased

#If it has 1 the count will look for another.

def hasAtLeastTwoUppercase(string):

count=0

for i in string:

if (i.isupper()):

count=count+1

else:

pass

if count >=2:

return True

else:

return False

#int(i)%2!=0 is looking for odd digits and if count is greater then or eqaul

#to 2 it will give give both odd digits

def hasAtLeastTwoOddDigits(string):

count=0

for i in string:

if i.isnumeric():

if int(i)%2!=0:

count=count+1

else:

pass

if count >=2:

return True

else:

return False

#looking fo the last character in a string [-1:]

def endsWithS(string):

if string[-1:]=='s' or string[-1:]=='S' :

return True

else:

return False

def ending(string):

if isValidDate(string):

date.append(string)

if isPalindrome(string):

palin.append(string)

if hasAtLeastTwoUppercase(string):

upper.append(string)

if hasAtLeastTwoOddDigits(string):

odd.append(string)

if endsWithS(string):

ends.append(string)

date=[]

palin=[]

upper=[]

odd=[]

ends=[]

for i in all :

ending(i)

print("Valid Dates:", date)

print("Palindromes", palin)

print("At least TWO Uppercase", upper)

print("At least TWO odd digits", odd)

print("Ends with s or S", ends)

# I took what i did in lab 3 and brought it into here.

#I set it up to look for the vowels in the string

#and if found with 2 return them to a list

def countVowels(string):

vowels=['a','e','i','o','u','A','E','I','O','U']

string=string.lower()

count=0

for i in string:

if i in vowels:

count = count + 1

if count>=2:

return True

else:

return False

vow=[]

for i in all:

if countVowels(i):

vow.append(i)

print("Has TWO or more Vowels",vow)

Print the lists, and be SURE TO LABEL your output! For example for the sample text file shown above: 504 111-22-3333 313 Hello by2e 11 cdc 232 toys abba HILLS 1111-22-3333 78087 111-22-111 98788 Valid dates: [ 12-30-2020 ] Palindromes: [ 313, 11, Cdc, 232, abba, 78087, 7 ] At least TWO Uppercase: [ Hello! What? Not now! Tues, HILLS At least TWO odd digits: [ 12-30-2020, 313, Bye235, 11, 02-29-2019, 78087,9878] Ends with sors: [ What? Not now! Tues, HILLS ] Print the lists, and be SURE TO LABEL your output! For example for the sample text file shown above: 504 111-22-3333 313 Hello by2e 11 cdc 232 toys abba HILLS 1111-22-3333 78087 111-22-111 98788 Valid dates: [ 12-30-2020 ] Palindromes: [ 313, 11, Cdc, 232, abba, 78087, 7 ] At least TWO Uppercase: [ Hello! What? Not now! Tues, HILLS At least TWO odd digits: [ 12-30-2020, 313, Bye235, 11, 02-29-2019, 78087,9878] Ends with sors: [ What? Not now! Tues, HILLS ]