MyOpenMath Assessment Week 8: Thursday MOM Homework Assignment - Chi Square Goodness of Fit 3/2/17, 5)36 PM Name: Vanessa Russell Exercises are set up so you can try the problem twice, then the answer will be shown on your third attempt. If you miss a problem on the exercises and want to improve your score, you can "Try a similar problem", which will give you a new question of the same type. You can keep on working on versions of a question until you get a perfect score on the exercises. #1 Points possible: 2. Total attempts: 3 At a stop sign, some drivers come to a full stop, some come to a `rolling stop' (not a full stop, but slow down), and some do not stop at all. We would like to test if there is an association between gender and type of stop (full, rolling, or no stop). We collect data by standing a few feet from a stop sign and taking note of type of stop and the gender of the driver. What are the hypotheses for testing for an association between gender and type of stop? H0: Males and females are equally likely to come to a full stop. HA: Males and females are not equally likely to come to a full stop. H0: Gender and type of stop are associated. HA: Gender and type of stop are independent. H0: Gender and type of stop are independent. HA: Gender and type of stop are associated. H0: Males and females are equally likely to come to a rolling stop. HA: Males are more likely than females to come to a rolling stop. #2 Points possible: 2. Total attempts: 3 You are conducting a multinomial hypothesis test ( = 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Observed Expected Category Frequency Frequency A 13 B 16 C 14 D 22 E 24 Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations. https://www.myopenmath.com/assessment/printtest.php Page 1 of 3 MyOpenMath Assessment 3/2/17, 5)36 PM What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.) 2 = What are the degrees of freedom for this test? d.f.= What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) greater than This test statistic leads to a decision to... reject the null accept the null fail to reject the null accept the alternative As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected. There is not sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected. The sample data support the claim that all 5 categories are equally likely to be selected. There is not sufficient sample evidence to support the claim that all 5 categories are equally likely to be selected. https://www.myopenmath.com/assessment/printtest.php Page 2 of 3 MyOpenMath Assessment 3/2/17, 5)36 PM #3 Points possible: 2. Total attempts: 3 You are conducting a multinomial Goodness of Fit hypothesis test for the claim that the 4 categories occur with the following frequencies: Ho : pA = 0.2; pB = 0.3; pC = 0.3; pD = 0.2 Complete the table. Report all answers accurate to three decimal places. Category Observed Expected Frequency Frequency A 35 B 51 C 35 D 44 What is the chi-square test-statistic for this data? 2 = What is the P-Value? P-Value = For significance level alpha 0.1, What would be the conclusion of this hypothesis test? Reject the Null Hypothesis Fail to reject the Null Hypothesis Report all answers accurate to three decimal places. https://www.myopenmath.com/assessment/printtest.php Page 3 of 3 MyOpenMath Assessment 3/2/17, 5)36 PM Week 8: Thursday MOM Homework Assignment - Chi Square Goodness of Fit Name: Vanessa Russell Exercises are set up so you can try the problem twice, then the answer will be shown on your third attempt. If you miss a problem on the exercises and want to improve your score, you can "Try a similar problem", which will give you a new question of the same type. You can keep on working on versions of a question until you get a perfect score on the exercises. #1 Points possible: 2. Total attempts: 3 At a stop sign, some drivers come to a full stop, some come to a `rolling stop' (not a full stop, but slow down), and some do not stop at all. We would like to test if there is an association between gender and type of stop (full, rolling, or no stop). We collect data by standing a few feet from a stop sign and taking note of type of stop and the gender of the driver. What are the hypotheses for testing for an association between gender and type of stop? H0: Males and females are equally likely to come to a full stop. HA: Males and females are not equally likely to come to a full stop. H0: Gender and type of stop are associated. HA: Gender and type of stop are independent. H0: Gender and type of stop are independent. HA: Gender and type of stop are associated. H0: Males and females are equally likely to come to a rolling stop. HA: Males are more likely than females to come to a rolling stop. #2 Points possible: 2. Total attempts: 3 You are conducting a multinomial hypothesis test ( = 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Observed Expected Category Frequency Frequency A 13 B 16 17.800 C 14 17.800 D 22 17.800 E 24 17.800 17.800 Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations. https://www.myopenmath.com/assessment/printtest.php Page 1 of 3 MyOpenMath Assessment 3/2/17, 5)36 PM What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.) 5.438 2 = What are the degrees of freedom for this test? d.f.= 4 What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = 0.2452 The p-value is... less than (or equal to) greater than This test statistic leads to a decision to... reject the null accept the null fail to reject the null accept the alternative As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected. There is not sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected. The sample data support the claim that all 5 categories are equally likely to be selected. There is not sufficient sample evidence to support the claim that all 5 categories are equally likely to be selected. https://www.myopenmath.com/assessment/printtest.php Page 2 of 3 MyOpenMath Assessment 3/2/17, 5)36 PM #3 Points possible: 2. Total attempts: 3 You are conducting a multinomial Goodness of Fit hypothesis test for the claim that the 4 categories occur with the following frequencies: Ho : pA = 0.2; pB = 0.3; pC = 0.3; pD = 0.2 Complete the table. Report all answers accurate to three decimal places. Category Observed Expected Frequency Frequency A 35 33.000 B 51 49.500 C 35 49.500 D 44 33.000 What is the chi-square test-statistic for this data? 2 = 8.081 What is the P-Value? P-Value = 0.0444 For significance level alpha 0.1, What would be the conclusion of this hypothesis test? Reject the Null Hypothesis Fail to reject the Null Hypothesis Report all answers accurate to three decimal places. https://www.myopenmath.com/assessment/printtest.php Page 3 of 3