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N2(g)+3F2(g) +2NF3(g) AH,98= -426 kJ mol! The following questions relate to the synthesis reaction represented by the chemical equation in the box above. a. Calculate
N2(g)+3F2(g) +2NF3(g) AH,98= -426 kJ mol! The following questions relate to the synthesis reaction represented by the chemical equation in the box above. a. Calculate the standard enthalpy change, AH, that occurs when a 3.256 mol sample of NF3(g) is formed from N2(g) and F2(g) at 1.00 atm and 298 K. The enthalpy change in a chemical reaction is the difference between energy absorbed in breaking bonds in the reactants and energy released by bond formation in the products. b. How many bonds are formed when two molecules of NF3 are produced according to the equation in the box above? c. Use both the information in the box above and the table of average bond enthalpies below to calculate the average enthalpy of the F - F bond. Bond Average Bond Enthalpy (kJ mol!) NEN 946 N-F 272 F-F
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