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n=50 Thank you 4- The result of sieve analysis of three aggregate samples (A, B, and C) are given below. a) Design a new aggregate
n=50
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4- The result of sieve analysis of three aggregate samples (A, B, and C) are given below. a) Design a new aggregate mixture and calculate the mixing ratios of each to confirm TS limits. (important note :maximum aggregate size of the new mixture must be d max=16 mm) b) Draw the grading curve of new aggregate sample and discuss the result. c) Calculate the fineness modulus of each and new mixture. Sieve size (mm) 31,5 16 8 4 1 0,5 0,25 Pan A. Passed (%) 100 (10+0.1n) 0.9 0.2 0.2 0.2 0.2 0.2 0 B. Passed (%) 100 100 (42+0.1n) 0.5 0.2 0.2 0.2 0.2 0 C. Passed(%) 100 100 100 79.0 (47+0.1n) 26.8 16.7 12.5 0 TS706-A32 (%) 100 62 38 23 14 8 6 2 0 TS706-B32 (%) 100 80 62 47 37 28 18 8 0 TS706-C32 (%) 100 89 77 66 53 42 28 15 0 TS706-A16 (%) 100 60 36 21 12 3 0 TS706-B16 (%) 100 76 56 42 32 8 0 TS706-C16 (%) 100 88 74 62 49 18 0 4- The result of sieve analysis of three aggregate samples (A, B, and C) are given below. a) Design a new aggregate mixture and calculate the mixing ratios of each to confirm TS limits. (important note :maximum aggregate size of the new mixture must be d max=16 mm) b) Draw the grading curve of new aggregate sample and discuss the result. c) Calculate the fineness modulus of each and new mixture. Sieve size (mm) 31,5 16 8 4 1 0,5 0,25 Pan A. Passed (%) 100 (10+0.1n) 0.9 0.2 0.2 0.2 0.2 0.2 0 B. Passed (%) 100 100 (42+0.1n) 0.5 0.2 0.2 0.2 0.2 0 C. Passed(%) 100 100 100 79.0 (47+0.1n) 26.8 16.7 12.5 0 TS706-A32 (%) 100 62 38 23 14 8 6 2 0 TS706-B32 (%) 100 80 62 47 37 28 18 8 0 TS706-C32 (%) 100 89 77 66 53 42 28 15 0 TS706-A16 (%) 100 60 36 21 12 3 0 TS706-B16 (%) 100 76 56 42 32 8 0 TS706-C16 (%) 100 88 74 62 49 18 0Step by Step Solution
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