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Name: 5 . ( 3 points ) LCS DP table. In the LCS problem, we are given as input two sequences, x = ( :

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5.(3 points) LCS DP table. In the LCS problem, we are given as input two sequences, x=(:x1,x2,dots,xm:) and Y=(:y1,y2,dots,yn:) and would like to find a longest subsequence common to both. Towards this end, we defined c[i,j]:=l length of LCS of xi and Yj, DS table of entries c[i,j]. ii) Give an LCS of x and Y
\table[[,j,0,1,2,3,4],[i,,yj,B,C,A,B
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