1. National Bearings manufactures bearings at plants located in Portland Oregon, Houston Texas, and Jacksonville Florida. To measure employee knowledge of Total Quality Management (TQM), six employees were randomly selected at each plant and tested. The test scores for these employees are given below. Mangers want to know if, on average, knowledge of TQM is equal across the 3 plants. Test equality of mean scores at proportional to = 0.05. Hint: What statistical procedure is used to test equality of three population means?

Observation 1 2 3 4 5 6

Portland 85 75 82 76 71 85

Houston 71 75 73 74 69 82

Jacksonville 59 64 62 69 75 67

a.The F value of 3.419 is < the F critical value of 3.682, therefore do not reject equality of means. Knowledge of TQM is equal across the 3 plants.

b.The F value of 1.326 is < the F critical value of 3.682, therefore do not reject equality of means. Knowledge of TQM is equal across the 3 plants.

c.The F value of 9 is > the F critical value of 3.682, therefore do not reject equality of means. Knowledge of TQM is not equal across the 3 plants.

d.The F value of 6.349 is > the F critical value of 3.682, therefore do not reject equality of means. Knowledge of TQM is not equal across the 3 plants.

2.A air quality instrument logs 0 when standards are not met and 1 when standards are met. The log is saved to file DATA. First, compute the proportion meeting standards as the mean of Air Quality values. Second, at alpha = 0.10 (sensitive, exploratory), test the hypothesis that proportion of times that air quality meets standards is at least 90%.

Time 0:00:00 0:00:30 0:01:00 0:01:30 0:02:00 0:02:30 0:03:00 0:03:30 0:04:00 0:04:30 0:05:00 0:05:30 0:06:00 0:06:30 0:07:00 0:07:30 0:08:00 0:08:30 0:09:00 0:09:30 0:10:00 0:10:30 0:11:00 0:11:30 0:12:00 0:12:30 0:13:00 0:13:30 0:14:00 0:14:30 0:15:00 0:15:30 0:16:00 0:16:30 0:17:00 0:17:30 0:18:00 0:18:30 0:19:00 0:19:30 0:20:00 0:20:30 0:21:00 0:21:30 0:22:00 0:22:30 0:23:00 0:23:30

Air Quality 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 1 1 1 0 1 0 1 0 1 1 0 1 0 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1

A. The pvalue of 0.006 indicates that the data provide overwhelming evidence against H0: pie greater than or equal to 0.90. H0 is rejected at alpha =0.10. Send out an air quality alert.

B. The pvalue of 0.966 indicates that the data provide insignificant evidence against H0: pie greater than or equal to 0.90. H0 is not rejected at alpha =0.10. The Status quo remains unchanged.

C. None of the answers are correct.

D. The pvalue of 0.022 indicates that the data provide strong evidence against H0: pie greater than or equal to 0.90. H0 is rejected at alpha =0.10. The status quo has changed.

E. The pvalue of 0.062 indicates that the data provide weak evidence against H0: pie greater than or equal to 0.90. H0 is rejected at alpha =0.10.

3.To test whether the mean time to mix a batch of adhesive is thesame formachines produced by

four manufacturers, TiteBondMax obtained DATA on the time (minutes) needed to mix the materials. Test whether the machines have equal mean mixing time at

A 25 23 21 23

B 23 21 23 24

C 25 25 25 21

D 27 26 27 26

A The data provide insignifi cant evidence against HO: Equal means at pvalue

0.514. The machine are considered equal.

B None of the answers are correct.

C The data provide weak evidence against HO: Equal means at pvalue 0.072. Equality of means

remains plausible.

D The data provide strong evidence against HO: Equal means at pvalue 0.013. The mixing machines

are not all equal.

E The data provide extreme evidence against HO: Equal means at pvalue 0.001. The mixing machines

are not all equal.

F The pvalue 0.0001is extreme evidence that the machines are not all the same.

4..TO BALANCE INVENTORY AT OTTO'S OPTOMETRY, CUSTOMER GENDER AND EYE CONDITION WERE COLLECTED IN DATA. MAKE A 2X2 PIVOT TABLE WITH GENDER IN ROWS AND EYE CONDITION IN COLUMNS. THE PIVOT TABLE IS

Customer # 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84

Eye Condition Farsighted Bifocals Nearsighted Farsighted Nearsighted Farsighted Farsighted Nearsighted Nearsighted Farsighted Bifocals Farsighted Farsighted Farsighted Farsighted Farsighted Nearsighted Bifocals Farsighted Farsighted Farsighted Bifocals Farsighted Nearsighted Nearsighted Bifocals Nearsighted Farsighted Bifocals Nearsighted Farsighted Bifocals Farsighted Bifocals Bifocals Farsighted Bifocals Farsighted Bifocals Bifocals Farsighted Farsighted Bifocals Farsighted Farsighted Farsighted Bifocals Farsighted Farsighted Bifocals Nearsighted Bifocals Farsighted Farsighted Farsighted Bifocals Farsighted Farsighted Farsighted Nearsighted Farsighted Nearsighted Farsighted Farsighted Bifocals Farsighted Bifocals Farsighted Farsighted Farsighted Bifocals Farsighted Bifocals Farsighted Farsighted Farsighted Farsighted Farsighted Farsighted Farsighted Farsighted Farsighted Farsighted Farsighted

Gender Male Male Male Male Female Male Male Female Male Male Male Female Male Male Male Male Male Female Male Male Male Male Female Male Female Female Female Female Male Female Male Female Male Female Female Female Male Male Female Male Male Female Female Female Male Male Female Female Female Male Male Female Female Female Male Female Female Male Male Male Female Male Female Female Female Male Male Female Male Female Female Male Female Female Female Female Female Female Female Female Female Female Female Female

a.

Fem 29, 9, 17 Total 55

Mal 9, 9, 11, Total 29

Total 38, 18, 28 Total 84

b.

Fem 22, 9, 16 Total47

Mal 17, 15, 5 Total 37

Total 39, 24, 21 Total 84

c.

Fem 13. 27, 5 Total 45

Male 8, 24, 7 Total 39

Total 21, 51, 12 Total 84

d. None of the answers match my table

e.

Fem 15, 9, 20 Total 44

Male 10, 15, 15 Total 40

Total 25, 24, 35 Total 84