Need a step by step explanation of this. Answer is 7.9. Formulas have to come from the sheet.

Consider a basketball at the top of a ramp. As the ball (radius = 0.235 m) rolls down the ramp, it reaches the bottom with a speed of 3.44 m/s. If the ramp is 72 cm high, how fast the ball rolling at the bottom? (This problem is asking about the angular speed.)

Round to 1 decimal.

Final Formula Sheet. Nothing can be written on this paper before the test. Q = mcAT Q = ml Ly = 2260000 - Ax Av Xf = *, tut kg V= A At At = = 20AT4 1 cal = 4.184 / At Ly = 333000 Of = Vo + at v; = v; + 2a(X - X.) kg f= Xitvattaxt? Cice = 2010 1 atm = 101300 Pa = P. g = 9.8 m/ 2 a = gsin(0) gt2 Csteam = 1996 Kg K Kg K 2 PoVo = PFVF KAAT a' + b= = c3 2.54 cm = 1 inch 1609 m = 1 mi At L Opp Adj Opp sin 8 = Hyp coS 0 = 7 Hyp tan 8 = - Adj Patpvi + pgh, = P. + - pvi + pgh, GMm F =. 1- = 2.24 mph 2n rad = 360 degrees = 1 rev Axis 72 Axis GM 100 cm = 1 m = 3.28 ft Hoop about Annular cylinder ap =. 9 - 72 (or ring) about r cylinder axis cylinder axis A = 17-2 C = 2ur G = 6.67x10-11 Nm3/kg EF = ma Fa = mg f = un 1 = MR2 1 = M(R + R) s = re v = wr a = ra Wf = wo + at w; = w8 + 2a(0, - 0;) Axis Axis Solid cylinder Solid cylinder w = 2nf Of = 0; + wt (or disk) about (or disk) about WE At cylinder axis central diameter v = 2arf Aw T = 7 a = - 1 = MR2 1- MR + Me At 2 Et = la T = rF sin O 1 = > mr2 Axis Axis Thin rod about Thin rod about axis through axis through one F YAL Impulse = FAt Impulse = mvf - mv. center 1. to end 1 to length A= L length P; = PF Li = L p = mv 1 = Mez L = Iw PE, = mgh 12 3 Axis Axis KE = =mv- PEsp = =kx2 Eth = fd Solid sphere Thin 2R W = AKE 28 spherical shell KErot = = Iw= W = Fd cos 0 about any diameter about any Eth = Q +W Eth = W - APE TEbefore = TEafter diameter P = Fv F = KAL 1 hp = 746 W 1 = 2MR 1 = 2MR 5 P-VF POV. PV = nRT W = P(V, - V.) 3 If Axis To Axis Slab about m K= = 1.38x10-23 - P = 77 R = 8.314- 1 axis through *mol K Hoop about center F 1 m3 = 1000 L FB = pVg R any diameter P A P = P. + pgd AL = aLAT P = + 1 = MR2 1= M (a2 + 62) 5 C =K - 273.15 AV = BV,AT 12 (F - 32) Cwater = 4184 4_ Kg K V= Smy SORT = , NKST = U 1mol = 6.02x1023 AV Q = At = Av AV1 = A,V2