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Question Completion Status: Question 1 Consider the following data relating to a particular project. Initial Cost ($) Annual Labor Cost ($) Annual Maintenance Cost ($) Other Annual Costs ($) Variable Cost per Unit ($) Residual Value ($) Selling Price per Unit ($) Annual Production (units)) Useful Life (years) MARR (%) 140,000 15,000 9,100 20,500 1.35 28,000 6.15 24,000 8 10 Project Balcance (in $) Year 0 1 2 3 4 5 6 7 8 -140,000.00 -83,400.00 -21, 140.00 47,346.00 122,680.60 205,548.66 296,703.53 396,973.88 535,271.27 Select the best answers 1. The discounted payback period is (A) 3.7 years (B) 2.3 years (C) 3.3 years (D) 2 years 2. The compound annual growth rate (CAGR) is (A) 8.2596 (B) 7.1496 (C) 48.7396 (D) 18.25% he 3. The future worth (FW) is (A) 5535,271.27 (B) $553,271.27 (0) $249,708.00 (D) $300,102.43 * Question Completion Status: 3. The future worth (FW) is (A) $535,271.27 (B) $553.271.27 (C) $249.708.00 (D) $300.102.43 4. The annual equivalent (AE) is (A) $46,860.27 (B) $15,480.71 (C) $46,806.27 (D) $19,119.29 5. The annual total cost is (A) $95,219.29 (B) $217,000.00 (0) $100,793.73 (D) $86,793.73 6. The break-even quantity is (A) 14,482 units (B) 14.249 units (C) 14,429 units (D) 15,608 units FORMULAS F = P(1+0) (1+1)-1 -1 P=F(1+1) (1+1)-1 P-1 logi) log(i+1) i(2+1) A=F (1+11 Depreciation (Initial Cost - Residual Value) x (1+1) Interest on Capital - Initial Cost x interest (+)-1 Question Completion Status: Question 1 Consider the following data relating to a particular project. Initial Cost ($) Annual Labor Cost ($) Annual Maintenance Cost ($) Other Annual Costs ($) Variable Cost per Unit ($) Residual Value ($) Selling Price per Unit ($) Annual Production (units)) Useful Life (years) MARR (%) 140,000 15,000 9,100 20,500 1.35 28,000 6.15 24,000 8 10 Project Balcance (in $) Year 0 1 2 3 4 5 6 7 8 -140,000.00 -83,400.00 -21, 140.00 47,346.00 122,680.60 205,548.66 296,703.53 396,973.88 535,271.27 Select the best answers 1. The discounted payback period is (A) 3.7 years (B) 2.3 years (C) 3.3 years (D) 2 years 2. The compound annual growth rate (CAGR) is (A) 8.2596 (B) 7.1496 (C) 48.7396 (D) 18.25% he 3. The future worth (FW) is (A) 5535,271.27 (B) $553,271.27 (0) $249,708.00 (D) $300,102.43 * Question Completion Status: 3. The future worth (FW) is (A) $535,271.27 (B) $553.271.27 (C) $249.708.00 (D) $300.102.43 4. The annual equivalent (AE) is (A) $46,860.27 (B) $15,480.71 (C) $46,806.27 (D) $19,119.29 5. The annual total cost is (A) $95,219.29 (B) $217,000.00 (0) $100,793.73 (D) $86,793.73 6. The break-even quantity is (A) 14,482 units (B) 14.249 units (C) 14,429 units (D) 15,608 units FORMULAS F = P(1+0) (1+1)-1 -1 P=F(1+1) (1+1)-1 P-1 logi) log(i+1) i(2+1) A=F (1+11 Depreciation (Initial Cost - Residual Value) x (1+1) Interest on Capital - Initial Cost x interest (+)-1