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Note: If your answer does not exactly match the correct choice, it is due to rounding of intermediate calculations. To avoid the discrepancy, do all your calculations in Excel without rounding. Questions 1-4 are based on the following: A statistics instructor asks each student in his class to report how much the student spent on textbooks for the semester. The gures reported by students are shown below. 290 325 460 280 565 855 690 565 525 650 695 530 345 340 510 495 315 550 345 745 535 400 380 485 515 410 540 595 295 510 545 595 450 620 430 130 270 420 415 270 625 420 430 545 525 615 180 450 665 870 500 300 540 260 745 505 270 415 240 530 210 750 405 450 350 260 575 330 405 545 200 215 455 855 545 310 300 540 115 685 365 270 750 815 645 405 545 570 635 555 375 330 120 560 720 520 500 530 580 280 355 695 630 380 955 295 455 460 555 270 685 510 690 230 480 535 385 325 910 715 410 285 460 210 415 435 735 190 Treat the data above as POPULATION data. 1 The mean expenditure on textbooks by all students is: a $460.44 b $465.09 C $469.79 C] $474.53 32 D-nu'm 33 D-nu'm 34- D-nu'm 35 D-nu'm The middle interval around the population proportion which captures 95% of sample proportions of vehicles that exceed the speed limit is: 0 .81 8 0.882 What was the sample size to build this interval 429 504- 531 559 Among adult residents of a certain state ?0% more than 12 years of schooling. We want to build a middle interval (pl, pg} centered at TI: = 0.?0 such that it captures 9 8% of all sample proportions within i 0.0 25 [2.5 percentage points] from the population proportion, what is the required sample size? 1883 1819 1 'Jr' 5 I" 1698 Rick O'Shea is one of the two candidates running for the governor of a Midwestern state. Suppose Rick 0' Shea has 4-? percent of the votes among all the voters in the state. Just before the election a local TV news polls a random sample of 520 voters. What is the probability that the poll will predict Rick O'Shea winning the election? 0.0690 0.0?6? 0.0852 0.094? What should the sample size be in order to reduce the probability of wrongly predicting Rick O'Shea's victory to 0.025? 1064 994- 929 868 2 The variance of the expenditure on textbooks by all students is: a 31,237.97 1) 30,928.69 C 30,622.46 d 30,319.27 The instructor takes a random sample of size n = 6 from the population data and obtains the following sample data: x 375 720 6 15 595 5 15 685 3 The sample mean is: a $595.91 b $590.01 C $584.17 d $578.38 4- The sample variance is: a 13,036.81 b 13,823.19 C 14,705.52 d 15,644.17 5 If we take random samples of size n = 6 from this population, the number of possible samples is: a 5,965,972,320 b 5,423,611,200 c 4,930,555,636 d 4,482,323,305 6 The expected value [mean] of sample means is equal to: a $493.70 b $434.02 c $474.53 d $465.23 7 The variance of sample means is: a 5412.5 b 5154.8 (2 15644.2 d 13036.8 8 The sample standard deviation is, a 140.69 b 135.28 C 130.08 d 125.08 9 The standard error of the sample mean is, a 74.67 b 71.80 c 69.04 d 66.38 ' 270 HW4 | Sheet1 I .-J.-. Questions 10- 18 are related to the following information A population has a mean of 1285.6 and standard deviation of 172.8. 10 A random sample of size n = 75 selected from this population. What is the probability that the sample mean exceeds 1310? a 0.1913 b 0.1594 c 0.1328 d 0.1107 11 What fraction ofthe means from samples of size 75 are below 1265? a 0.1509 b 0.1313 c 0.1141 Cl 0.0992 12 What fraction of the means from random samples of size 75 are within :25 from the population mean? a 0.7898 b 0.8227 c 0.8570 d 0.8927 13 What is the margin of error for the middle interval that captures 95% of the sample means from samples of size 75? a 43.12 b 41.06 c 39.11 d 37.25 14 The middle interval that captures 95% of the means from samples of size 68 is, 1233.5 1337.7 1238.3 1332.9 1242.6 1328.6 1246.5 1324.7 a b c d 15 Dno'm 16 Dncr'm 17 Dno'm 18 Dno'm Suppose we double the sample size to n = 2 >