Need help filling it out. I tried to do it on my own however I still don't get it.

Substance Specific Heat (J/g*C) Variable Number Water 4.184 mass 46 g Granite 0.803 specific heat 0.803 J/g'C Mercury 0.140 final temp 15.5 C Silver 0.235 initial temp 8.5 .C Copper 0.385 Iron 0.449 What is the change in temperature (AT)? 15.5 - 8.5 =7 'C Table AT Answer Rxn Edit my response V X X Calculate the energy (heat) of the object. q = mCAT joules