Need help of the following problem attached below:

There are two trafc Eights on my wa\\_.Ir to work. Let X; be the number of Fights at which I must stop, and suppose that the distribution of X1 is as foriows. x; l 0 1 2 ,u = 0.9, a2 = 0.69 p(x1) I 0.4 0.3 0.3 Let X2 be the number of fights at which I must stop on the way home; X2 rs :ndependent of X1. Assume that X2 has the same drstnbution as X1, so that X1, X2 is a random sampie of s'ze n = 2. [Give answers accurate to 2 decimal piaces.) (a) Let Ta = X; + X2, and determine the probability distnbutron of To. To | [I 1 2 3 4 P(Ta) 'UJG 'f 0.24 i 0.33 J 018 ,I 0.09 ,p (b) Calcuiate \"To- 1.80 'p How does It reFate to ,u, the population mean? Mo = 2 I ' :1 (c) Calcuiate 052. 0.69 x How does it relate to 02, the popufation vanance? (sq-02 = 2 V - a2