need help with this question

In six packages of "The Flintstones@ Real Fruit Snacks" there were eight Bam-Bam snack pieces. The total number of snack pieces in the six bags was 68. We wish to calculate a 96% confidence interval for the population proportion of Bam-Bam snack pieces. - Part (a) Define the random variables X and P' in words. O X is the number of Bam-Bam snacks in a sample of 68 snack pieces. P' is the proportion of Bam-Bam pieces in a bag of snacks. Xis the proportion of Bam-Bam snacks in a sample of 68 snack pieces. P' is the proportion of Bam-Bam pieces in a bag of snacks. X is the number of Bam-Bam snacks in a bag of snacks. P' is the number of Bam-Bam pieces in a sample of 68 snack pieces. O X is the proportion of Bam-Bam snacks in a bag of snacks. P'is the proportion of Bam-Bam pieces in a sample of 68 snack pieces. Part (b) Which distribution should you use for this problem? (Enter your answer in the form z or toywhere of is the degrees of freedom.) Explain your choice. O The Student's t-distribution should be used because v npq $ 10, which implies a small sample. The standard normal distribution should be used because we are interested in proportions. The Student's t-distribution should be used because we do not know the standard deviation. The binomial distribution should be used because the two outcomes are "Bam-Bam" and "Not Bam-Bam". Part (c) Calculate p'. (Round your answer to three decimal places.) p'=- Part (d) Construct a 96% confidence interval for the population proportion of Bam-Bam snack pieces per bag. (Round your answers to three decimal places.) (i) State the confidence interval. (ii) Sketch the graph. CL = = N R = X (iii) Calculate the error bound. Part (e) (e) Do you think that six packages of fruit snacks yield enough data to give accurate results? Why or why not? Yes, this is clearly a simple random sample. No, we do not know if this sample was obtained from a simple random sample