Question
need java code 1. Create a hashmap that is made of elements HashElement(int Key, String Value). The size of hashmap will be 100. Implement the
need java code
1. Create a hashmap that is made of elements HashElement(int Key, String Value). The size of hashmap will be 100. Implement the following methods for the hashmap:
a. put(int Key, String Value): Puts the key value pair in the hashmap at a certain index. You need to implement a simple hash function H(Key)=Key mod mapsize to find the index where you will put the pair. If collision occurs, i.e., a pair already exists in that index and the key is not the same as the current key, then you will use this function to resolve the collision, H(x)=(7*H(x)+1) mod mapsize, until you get an empty slot. If the index is already full and the keys are the same, just replace the old value with the new one.
b. get(int Key): Gets the value associated with the Key. You should not do linear search throughout the hashmap for the key, rather you will calculate the index using the hash function stated above, go directly to that index and retreive the value.
2. Write a driver program to test your implementation of hashmap. Allow the user to put or get data.
3. Implement linear probing to put a new value in your HashMap. The sequence of probes are: H(x) mod mapsize, (H(x) +1) mod mapsize, (H(x)+2) mod mapsize, (H(x)+3) mod mapsize and so on.
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