Needing help correct this practice question.

In an article in the Journal ofAdven'ising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 141 use humor, while a random sample of 500 television ads in the United States reveals that 122 use humor. (a) Set up the null and alternative hypotheses needed to determine whetherthe proportion of ads using humor in the United Kingdom differs from the proportion of ads using humor in the United States. IHO: p1 p2 = Q 0 versus Ha: p1 - p2 # a 0. (b) Test the hypotheses you set up in part a by using critical values and by setting 0 equal to .10, .05, .01, and .001. How much evidence is there that the proportions of UK. and US. ads using humor are different? (Round the proportion values to 3 decimal places. Round your answer to 2 decimal places.) - Reject 9 H0 at each value of (1; none 9 levidence. (c) Set up the hypotheses needed to attempt to establish that the difference between the proportions of U.K. and US. ads using humor is more than .05 (five percentage points). Test these hypotheses by using a pvalue and by setting C1 equal to .10, .05, .01, and .001. How much evidence is there that the difference between the proportions exceeds .05? (Round the proportion values to 3 decimal places. Round your 2 value to 2 decimal places and p-value to 4 decimal places.) p-value 0.2922 0 Reject 0 H0 at each value of u = .10 and a = .05; some 0 evidence. (d) Calculate a 95 percent confidence interval for the difference between the proportion of U.K. ads using humor and the proportion of U.S. ads using humor. Interpret this interval. Can we be 95 percent confident that the proportion of U.K. ads using humor is greater than the proportion of U.S. ads using humor? (Round the proportion values to 3 decimal places. Round your answers to 4 decimal places.) 95% of Confidence Interval 0. 1687 X 0.0483 X No X the entire interval is above zero