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not sure what to do Solution f(4) =64-16-28 -20 =0 : (x - 4) is a factor of f (x). f(x) = (x -4)(x2 +3x+5)

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Solution f(4) =64-16-28 -20 =0 : (x - 4) is a factor of f (x). f(x) = (x -4)(x2 +3x+5) f (xx) =0 = x = 4 or x +3x +5=0 -3+19-20 -3+v-11 If x + 3x+5=0 then x = = x = 4 is the only real root. What was the

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