Not sure why the answers in red are incorrect - please provide correct answers!

Use the following information for all parts: On a particular golf course, a sample of 48 golfers have a mean golf score of 75. Suppose the population standard deviation for this course is 4.6101. (a) Using the formula for a 90%% confidence interval as presented in lecture, fill in the blanks with the appropriate values for this problem for calculating the confidence interval below. To enter :I where x is any number, type sqrt(x). For example, \\/2 should be written as sqrt(2). 4.6101 4.6101 75 1.65 75 1.65 X to X V 48 V 48 (b) Using the formulas from part (a), calculate the 90% confidence intervals for the mean golf score of all golfers on this golf course. Round each answer to the nearest hundredth, 2 decimal places. 48.81 to 51.00 (c) Calculate the margin of error for the answer in part (b). Round the answer to the nearest hundredth, 2 decimal places. 1.10 (d) Using the formula for a 99% confidence interval as presented in lecture, fill in the blanks with the appropriate values for this problem for calculating the confidence interval below. To enter :I where x is any number, type sqrt(x). For example, v2 should be written as sqrt(2). 4.6101 4.6101 75 2.58 75 2.58 X to X 48 V 48 (e) Using the formulas from part (d), calculate the 99% confidence intervals for the mean golf score of all golfers on this golf course. Round each answer to the nearest hundredth, 2 decimal places. 48.19 X 51.62