Not your average Joe x Home X D21 Resources: Module Five - MAT-14 X m Southern New Hampshire Univer > V X F- CD snhu.mobius.cloud/modules/unproctoredTest. QuestionSheet ACADEMIC SUPPORT or in the learning modules. Question 12 Consider the function f (x) = 3sin ( (x -4) ) + 5. State the amplitude A, period P, and 3 points midline. State the phase shift and vertical translation. In the full period [0, P], state the maximum and minimum y-values and their corresponding x-values. Enter the exact answers. Amplitude: A = 3 Period: P = Midline: y = 5 The phase shift is 4 units to the right The vertical translation is up 5 units Hints for the maximum and minimum values of f (x): . The maximum value of y = sin (x) is y = 1 and the corresponding x values are x = , and multiples of 2 7 less than and more than this a value. You may want to solve ? (x - 4) = . . The minimum value of y = sin (x) is y = -1 and the corresponding x values are x = 31 and 2 multiples of 2 7 less than and more than this x value. You may want to solve ? (x - 4) = 2 . If you get a value for a that is less than 0, you could add multiples of P to get into the next cycles. . If you get a value for a that is more than P, you could subtract multiples of P to get into the previous cycles. For a in the interval [0, P], the maximum y-value and corresponding x-value is at: C= y = 8 Submit Assignment Quit & Save Back Question Menu Next(-960 i Sn hut mobius.cloud/mod \\ll eslunp rouoledTeslu estic n Sheel m Soulhem New Hampshlre Unwe x Amplitude: A : 3 Period: P : @ @ Midline: y : 5 The phase shi is 4mtsluwhenght . The vertical translation is up 5 units . Hints for the maximum and minimum values of f(1): The maximum value of y: sin(:) is y : 1 and the corresponding 1 values are 1 : g and multiples of 2 7r less than and more than this x value. You may want to solve % (w 7 4) = g. The minimum value of y : 3111(1) is y : 71 and the corresponding I values are a: : L; and multiples of 2 1r less than and more than this a: value. You may want to solve % (a: 7 4) : 37. If you get a value for .1: that is less than 0, you could add multiples of P10 get into the next cycles. If you get a value for :1: that is more than P, you could subtract multiples of P to get into the previous cycles. For m in the interval [0, P], the maximum y-value and corresponding m-value is at: = @I : 8 @- For I in the interval [0, P], the minimum yValue and corresponding Ivalue is at: 1: @I y: 2 @I SumetAssignmenl H Qu&53ve ' | Back H Question MenuA