Now find L0 and R0, the left and right halves of the state. L0=R0= What is the result of applying the expansion box to R0 ? E(R0)= What is the result of XORing the subkey with E(R0) ? k0E(R0)= We now apply the S-box transformation. S(k0E(R0))= Finally we apply the permutation box to complete the function f. f(R0)=P(S(k0E(R0)))= We can now compute the state of DES going into the next round. L1=R1=