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Now let's assume that the motion is such that the acceleration is constant and equal to a. Then, the position is given by the

Now let's assume that the motion is such that the acceleration is constant and equal to a. Then, the position ii. Starting with Equation (5-5) show that a t = a. Trial 1 2 3 4 5 6 7 8 9 10 11 12 Speed (m/s) 0.41 0.49 0.55 0.67 0.72 0.75 0.82 0.88 0.93 1.00 1.09 1.12

Now let's assume that the motion is such that the acceleration is constant and equal to a. Then, the position is given by the expression, st=at+vt+So where V, is the velocity of the body at t=0. In order to solve Equation (5-5) we need to know the two initial conditions Vo and So, in addition to the value of the constant acceleration a. m Motion with constant acceleration was first studied by Galileo Galilei using an inclined plane. The constant acceleration of gravity has the value g=9.81 near the Earth's surface. Only the component of this acceleration along the direction of motion acts on the body, so that if the plane is inclined at an angle Owith respect to the horizontal, the acceleration is given by, S a=gsin(9) (5-5) PROCEDURE Prelab Questions i. The inclined ramp used in this experiment provides a fairly accurate demonstration of motion with constant acceleration. Starting with Equation (5-5) show that vit = at +vo. (5-6) ii. Starting with Equation (5-5) show that a t = a. Trial 1 2 3 4 5 6 7 8 9 10 11 12 Speed (m/s) 0.41 0.49 0.55 0.67 0.72 0.75 0.82 0.88 0.93 1.00 1.09 1.12 Elapsed time (s) 0.48 0.57 0.65 0.78 0.84 0.88 0.96 1.03 1.09 1.17 1.28 1.32

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