number = 185

#You may modify the lines of code above, but don't move them! #When you Submit your code, we'll change these lines to #assign different values to the variables. # #The number above is given in base 10. Let's convert it to #base 2 and print it in binary. For example, 215 can be written #in binary as 11010111. # #Each digit of that string corresponds to a power of 2. The far #left digit represents 128, then 64, then 32, then 16, then 8, #then 4, then 2, and then finally 1 at the far right. # #To convert the number to binary, first check to see if it is #greater than or equal to 128. If it is, your first digit is 1. #If not, your first digit is 0. If the number was greater than #128, subtract 128 (because the 128 is captured by the first #digit of the string). # #Then, repeat that process for 64, 32, 16, 8, 4, 2, and 1. # #For example: # #215 is >= 128: 1 #87 is >= 64: 11 #23 is not >= 32: 110 #23 is >= 16: 1101 #7 is not >= 8: 11010 #7 is >= 4: 110101 #3 is >= 2: 1101011 #1 is >= 1: 11010111 # #Note that although we use 'if' a lot to describe this problem, #this can be done entirely with floor division and modulus. #Remember, if you convert a boolean to an integer, True becomes #1 and False becomes 0. # #Note that we always work with binary in 8-bit chunks: the #number 7 would be 00000111, not just 111. That's because inside #the computer, 8 1s and 0s make a byte, which is the smallest #practical unit of storage (rarely are bits used outside 8-bit #bytes). # #Print the string that results from this conversion.

#Add your code here!

python 3 and do not use if else statements. only use mathmatical, relational, and boolean operators please..