o, 236ten has one 5', leaving 236 - 125 = 111ten. Then 11 1 ten s, leaving 111 - 100 =11ten. Then 11ten has two 5s, leaving ten. Thus 236ten = 1421 five- Exercises for Section 1.3 1. Use the BasePlayer applet to practice counting in different 2. Write ten (this many: x x x x x x x x x x) in each of these s a. base four b. base five c. base eight 3. Write each of these. a. four in base four b. eight in base eight c. twenty in base twenty d. b in base b c. b2 in base b f. b3 + b2 in base b g. twenty-nine in base three h. one hundred fifteen in base i. 69ten, in base two j. 1728ten, in base twelve 4. Write the numerals for counting in base two, from one throug twenty. 5. How do you know that there is an error in each of these? a. ten = 24three b. fifty-six = 107 seven c. thirteen and three-fourths = 25.3 four L