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Observe that for a random variable Y that takes on values 0 and 1, the expected value of Y is defined as follows: E(Y)=0times Pr(Y
Observe that for a random variable
Y
that takes on values 0 and 1, the expected value of
Y
is defined as follows:\
E(Y)=0\\\\times Pr(Y
)
=
(
0)+1\\\\times Pr(Y
)
=
(
1)
\ Now, suppose that
x
is a Bernoull random variable with success probability
Pr(x
)
=
(
1)=p
. Use the information above to answer the following questions.\ Show that
E(x^(2))=p
.\
{
(
:E(x^(2))=,x+1,xp)=
}\ (Use the tool palette on the right to insert superscripts. Enter you answer in the same format as above)
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