Obtain the following first derivative formula * 0 (h2) for the truncation error;

Also for the following table values h = 0.2, use the above formula to approximate the value of f '(2.95).

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f'(x) ) 1 [-f(x + 2h) + 4f(x + h) - 3f(x)] 2h 2.95 3.05 3.15 3.25 3.35 y = f(x) 13.365 14.665 16.088 17.640 19.327