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On question 10 on Skill Builder: Topic 2.7 - Derivatives of sinx, cosx, e^x and lnx --> I got the derivative of g(x) by doing

On question 10 on Skill Builder: Topic 2.7 - Derivatives of sinx, cosx, e^x and lnx

--> I got the derivative of g(x) by doing 1+cosx and then to find the horizontal tangent, I set this equal to 0, then I got cosx=-1, could I simplify this to x= -1/cos?? I am confused how the solution to get the horizontal line was x=.

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