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One human being has a 3 D dimension of 1 . 7 - by - 0 . 5 - by - 0 . 3 m

One human being has a 3D dimension of 1.7-by-0.5-by-0.3 m (height, width, thickness). And he/she can swim up to 4 mph, i.e.,1.788 m/s, in water. The dynamic viscosity of water at 25 degC is 0.89 mPas and density is \rho =1000 kg/m3. Answer the following questions: 1) What is the characteristic length L of this human being? [2 points]2) What is the Reynolds number Re for this human being in water? [4 points] What is the unit of the calculated Reynolds number? [1 point] According to your calculated Reynolds number, is viscous or inertial forces dominant in this case? [1 point]3) If the swimmer is downscaled by 1000 times, making his/her dimension 1.7-by-0.5-by-0.3 mm. Re-calculate Re and re-answer the questions in subquestion (2). Note that the swimming speed should also be downscaled to 1.788 mm/s.[4 points]4) If the swimmer is downscaled again by 1000 times, making his/her dimension 1.7-by-0.5-by-0.3\mu m. Re-calculate Re and re-answer the questions in subquestion (2). Note that the swimming speed should also be downscaled to 1.788\mu m/s.[2 points]5) If the swimmer is downscaled again by 1000 times, making his/her dimension 1.7-by-0.5-by-0.3 nm. Re-calculate Re and re-answer the questions in subquestion (2). Note that the swimming speed should also be downscaled to 1.788 nm/s.[2 points]6) Discuss and explain how the swimmer will feel like when he/she swims in the scenarios described in subquestion (3),(4), and (5) using the Reynolds number values you calculated. [2 points] The Reynolds number is defined as Re =\rho uL/\mu where Re is the Reynolds number, \rho is the fluid density, u is the flow speed, L is the characteristic dimension, \mu is the fluid viscosity.

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