One property of automobile air bags that contributes to their ability to absorb energy is the permeability (ft /ft /min) of the woven material used to construct the air bags. Understanding how permeability is influenced by various factors is important for increasing the effectiveness of air bags. The effects of three factors, each at three levels, were studied: A (Temperature): 8 C, 50C, 75.C B (Fabric denier) : 420-D, 630-D, 840-D C (Air pressure): 17.2 kPa, 34.4 kPa, 103.4 kPa Temperature 80 Pressure Denier 17.2 34.4 103.4 420-D 73 157 332 80 155 322 630-D 35 91 288 433 98 271 840-D 125 234 477 111 233 464 Temperature 50 Pressure Denier 17.2 34.4 103.4 420-D 52 125 281 51 118 264 630-D 16 72 169 12 78 173 840-D 96 149 338 100 155 350Temperature 750 Pressure Denier 17.2 34.4 103.4 420-D 37 95 276 31 106 281 630-D 30 91 213 41 100 211 840-D 102 170 307 98 160 311 The hypotheses are as follows: Ho: all a;'s = 0 HoB: all Bi's = 0 Hoc: all 8 's = 0 HaA: at least one a, # 0 HaB: at least one B, * 0 Hac: at least one & # 0 HOAB: all y AB's = 0 AC'S = 0 HOAC: all Yik 's BC'S = 0 HOBC: all Yjk 'S HaAB: at least one y # # 0 Hac: at least one Yik # 0 HaBc: at least one Yjk BC + 0 HOBC: all Yijk'S = 0 HaBC: at least one yijk # 0 Analyze this data and state your conclusions (assume that all factors are fixed). (Round your answers for SS and MS to the nearest whole number and your answers for f and Foo, to two decimal places. ) Source df SS MS f Fo.01 A B C AB AC BC ABC Error TotalWhich null hypotheses should be rejected at a = 0.01? (Select all that apply.) O HOA O HOB O Hoc O HOAB O HOAC O HOBC O HOABC O No null hypotheses should be rejected. You may need to use the appropriate table in the Appendix of Tables to answer this