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only answers pls 1. The reflection of perpendicularly incident white light by a soap film in air has an interference maximum at 563 nm and
only answers pls
1.
The reflection of perpendicularly incident white light by a soap film in air has an interference maximum at 563 nm and a minimum at 422 nm, with no minimum in between. If n = 1.33 for the film, what is the film thickness, assumed uniform?Transmission through thin layers. In the gure, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) Part of the light ends up in material 3 as ray r3 (the light does not reect inside material 2) and r4 (the light reects twice inside material 2). The waves of r3 and r4 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). The table below provides the indexes of refraction n1, n2, and n3, the type of interference, and the wavelength A in nanometers of the light as measured in air. Give the second least thickness L. n1 n2 n3 Type L A 1.45 1.52 1.81 max 2nd 565 A Newton's ring apparatus is to be used to determine the radius of curvature of a lens (see the gure below). The radii of the nth and (n+20)th bright rings are measured and found to be 0.234 and 0.539 cm, respectively, in light of wavelength 503 nm. Calculate the radius of curvature of the lower surface of the lens in centimeters. Incident light \\3Step by Step Solution
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