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only part 4 of question needed. The freezing point of a 0.10m solution of mercury(I) nitrate is approximately 0.27C (Assuming that the person who prepared

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The freezing point of a 0.10m solution of mercury(I) nitrate is approximately 0.27C (Assuming that the person who prepared the solution thought it was HgNO3 ). Why do these data suggest that the formula of the mercury(I) ion is Hg22+ ? Calculate Tf for Hg2(NO3)2

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