outlook	temperature	play
sunny	hot	no
overcast	hot	yes
rainy	cool	yes
overcast	cool	yes
sunny	mild	no
rainy	mild	yes
overcast	mild	yes
sunny	cool	yes
rainy	hot	no

This is data mining related. Based on the table:

a) Which attribute has higher classification accuracy (class attribute is play)? Outlook, Temperature or they have the same classification accuracy

b) TRUE OR FALSE. Consider a generalized tuple of the type {A=V}, where A is outlook or temperature and V is chosen from the set of possible values of the corresponding attribute (according to the data). The minimal number of such generalized tuples needed to cover all tuples from class yes (possibly covering tuples from class no) is TRUE OR FALSE

c) Which formula applies to computing the information in the split based on the values of outlook?

I=-(3/3)*log(3/3)-(1/3)*log(1/3)-(2/3)*log(2/3)

OR

I=(3/9)*info([3,0])+(3/9)*info([1,2])+(3/9)*info([2,1])